Japantluii

AC' refers to those elements which are present in A but not present in C Let's think out what their intersection gives elements which are present in A and B but not present in C This also turns out to be equal to E1 So all the three expressions are sameN @CALEIDO i J C h j n N @B f ށ@cotton63 @linen37 Y @Italy C ^ A A t X A C M X Ȃǂ̃ b p ͂ Ƃ A E ̃\ t @ J Œ 闝 R ́A ō ̔ G Ɣ F ɂ ܂ B M l X \ قǂ̎ т cotton linen ̃v ~ A t @ u b N ł BDistributive Law Property of Set Theory Proof First law states that taking the union of a set to the intersection of two other sets is the same as taking the union of the original set and both the other two sets separately, and then taking the intersection of the results Let x ∈ A ∪ (B ∩ C) If x ∈ A ∪ (B ∩ C) then x is either in Let A A B C D E F B C D E G And C B C F G Be Subsets Of T U n b c